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# Solve the 6-Pointed Magic Star Problem
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# Use the numbers 1-12 to give equal sums in each of 6 lines making
# up the star shape below. Eg: B+C+D+E = 26, B+F+I+L = 26, etc.
#
# A
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# B C D E
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# F G
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# H I J K
#
# L
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This is a very old puzzle, first proposed by Henry E. Dudeney and catalogued by Donald E. Knuth with the entry:
+50(15)210 X261 A star puzzle: Magic 6-star of {1,2,…,12} with sums 26
meaning: Volume 50, (1915), page 210, puzzle number X261.
This can be considered a problem in 12 unknowns with only 6 equations (the 6 straight lines making up the figure). There are therefore apparently 6 degrees of freedom. A straight-forward approach would be to choose A, B, C, D, F and G, (E must be equal to 26 – B – C – D, of course) and then calculate the other letters from the obvious relations. This would appear to give 12 x 11 x 10 x 9 x 8 x 7 solutions (12 choices for A, 11 for B etc) or 665,280 in all.
Unfortunately, many of these choices give values which are less than 1 or greater than 12 for some letters E or H – L. When these are eliminated, there are still many illegal combinations left where some numbers are duplicated. Finally the number of solutions is whittled down to 960.
But the figure has 12-fold symmetry (6 rotations x 2 reflections), so we find the number of unique solutions to be (960 / 12) or just 80.
Hardly any deep mathematical knowledge was required, just brute-force and symmetry.
We have written a simple Perl program to produce the 80 solutions in 5 seconds of PC elapsed time and invite reader solutions, too.
Here are the first few we have found:
N a b c d e f g h i j k l P V
1: 1 2 4 12 8 10 6 11 5 3 7 9 Peak: 38 Valley: 40
2: 1 2 6 10 8 12 4 7 3 5 11 9 Peak: 38 Valley: 40
3: 1 2 7 11 6 8 5 10 4 3 9 12 Peak: 40 Valley: 38
4: 1 2 7 12 5 10 4 8 3 6 9 11 Peak: 36 Valley: 42
5: 1 2 8 9 7 11 4 6 3 5 12 10 Peak: 38 Valley: 40
6: 1 2 8 10 6 12 4 5 3 7 11 9 Peak: 34 Valley: 44
7: 1 2 9 12 3 6 8 10 7 4 5 11 Peak: 32 Valley: 46
8: 1 2 10 11 3 8 5 7 4 6 9 12 Peak: 34 Valley: 44
9: 1 3 4 8 11 12 7 9 5 2 10 6 Peak: 40 Valley: 38
10: 1 3 5 11 7 12 4 8 2 6 10 9 Peak: 38 Valley: 40
11: 1 3 6 12 5 11 4 8 2 7 9 10 Peak: 36 Valley: 42
12: 1 3 7 11 5 6 10 12 8 2 4 9 Peak: 34 Valley: 44
13: 1 3 7 11 5 12 4 6 2 8 10 9 Peak: 34 Valley: 44
14: 1 3 7 12 4 8 11 10 9 5 2 6 Peak: 26 Valley: 52 *
....
A little curiosity: solution number 14 shows the sum of the Peaks also to be 26. Six solutions have this property; another six have the sum of the Valleys to be 26.
[ Peak Sum = A + E + K + L + H + B, Valley Sum = D + G + J + I + F + C ]